Bash script that checks if a given number is even or odd

Here are the steps to write a simple Bash script that checks if a given number is even or odd:

1. Create a new file as mentioned below.

vi check_number.sh

2. Copy and paste below simple Bash script that prompts the user for a file name, reads the contents of the specified file, and displays them on the terminal.

#!/bin/bash

# Prompt the user for a number

echo "Enter a number:"

read number

# Check if the number is even or odd

if ((number % 2 == 0)); then

echo "$number is even."

else

echo "$number is odd."

fi

Now, let’s break down the script:

1. Shebang (#!/bin/bash):

– This line indicates that the script should be executed using the Bash shell.

2. Prompt for User Input:

– echo “Enter a number:” prompts the user to enter a number.

– read number reads the user’s input and stores it in the variable number.

3. Check if Number is Even or Odd:

– if ((number % 2 == 0)); then checks if the remainder of the number divided by 2 is equal to 0.

– If the condition is true, it means the number is even.

4. Display Result:

– echo “$number is even.” is executed if the number is even.

– else is part of the conditional statement and is executed if the number is odd.

– echo “$number is odd.” is executed if the number is odd.

3. Save and close the “vi” editor by pressing “Esc” key and type :wq! and press “enter” key.

4. Make sure to give execute permissions to the script before running it. You can do this by running the following command in the terminal:

chmod +x check_number.sh

Note : Replace “check_number.sh” with the actual name you save the script as.

The script will prompt you to enter a number, and it will then tell you whether the number is even or odd.

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